Evaluation of anti-log

QUESTION
In my kind of work, log function is very unusual. I have found that log(number)= works fine - in that answer is correct.

y: 4.601 log(y) = 0.66285

But now I need to evaluate the anti-log…can be easily done on pocket calculator (via inverse/shift); but how is it done in Mathcad?

By experimentation…

10^log(y) = 4.601 works, but is it correct procedure?; any neater solution?

REPLIES

occupant
Create your own function: alog(x):10^x where “x” would your previous log()

SOURCE
https://www.eng-tips.com/viewthread.cfm?qid=370739
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